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The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4

The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4



 
 
 
 
 
 
 

The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4

And this is the result when I run the python script:
Found 4 files matching:/home/user/Desktop/YIFY/YIFY (scary results)
Type of file

908adb44bc. Dhund Lenge Manzil Hum tamil movies · The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4.

Here is my code:
$movies = array();
foreach ($lines as $row) {
if (!strpos($row, ‘The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4’)) {
$name = trim($row, ‘[‘);
$path = trim($row, ‘]’);
array_push($movies, array(‘name’ => $name, ‘path’ => $path));
}
}
$file = fopen(“${movies[0][‘name’]}.txt”, “r”);
$files = fopen(“${movies[0][‘path’]}”, “r”);

This will show the name of all files but not their path. I need to loop through the file and retrieve the file path from the array. Any ideas?

A:

You just need to use explode to split the line by the delimiter of the entry:
if (!strpos($row, ‘The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4’)) {
$entry = explode(‘ ‘, trim($row, ‘[‘));
// note that you didn’t show code to pull out the name, but
// it is stored in the $entry array
$name = trim($entry[0]);
$path = trim($entry[1]);
array_push($movies, array(‘name’ => $name, ‘path’ => $path));
}

Note that I also added a check of if the line starts with The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.YIFY.mp4, for the example you show above, The.Pursuit.Of.Happyness.2006.720p.BrRip.x264.Y
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